grouping and indexing

Question

Hi,

I would like to create a vector to index a group. Assume that I have the following data set:

a = { 1 1 1 50,
      1 1 2 80,
      1 2 1 60,
      2 1 1 100,
      2 1 2 90,
      2 2 1 40,
      2 2 2 50,
      3 1 1 100,
      3 1 2 70,
      3 1 3 60,
      3 2 1 20,
      3 2 2 30,
      3 2 3 30,
      3 2 4 20 };

first col. indicating the country, second col. indicating the region within the country (each country has two regions) and the third col. is the city index. I would like to have an index for the unique regions. For this example it would be :

Any suggestions on how to do this for a large scale matrix?

Best

2 Answers

Your Answer

aptech · Answer 1

You can:

Use a matrix-vector multiply to convert the first two (or any number) of columns into an integer id for the column.
Find the unique integer id's.
Convert the 2 digit integer id's to a list of sequential integer id's.

a = { 1 1 1 50,
      1 1 2 80,
      1 2 1 60,
      2 1 1 100,
      2 1 2 90,
      2 2 1 40,
      2 2 2 50,
      3 1 1 100,
      3 1 2 70,
      3 1 3 60,
      3 2 1 20,
      3 2 2 30,
      3 2 3 30,
      3 2 4 20 };

// Convert first three columns into an integer,
// i.e. { 1 1 } -> 11, { 3 1 } -> 31
ncols = 2;
m = { 10, 1 };
grps = a[.,1:ncols]*m;

// Get unique groups
grps_unique = unique(grps);

// Convert groups into sequential class groups
idx = reclassify(grps, grps_unique, seqa(1, 1, rows(grps_unique)));

link

aptech

1,773

darushka · Answer 2

Thank you! I was not aware of the reclassify function. Up to that, I actually followed the same steps, but I was stuck with that.

link

darushka

12

aptech · Answer 3

You can:

Use a matrix-vector multiply to convert the first two (or any number) of columns into an integer id for the column.
Find the unique integer id's.
Convert the 2 digit integer id's to a list of sequential integer id's.

a = { 1 1 1 50,
      1 1 2 80,
      1 2 1 60,
      2 1 1 100,
      2 1 2 90,
      2 2 1 40,
      2 2 2 50,
      3 1 1 100,
      3 1 2 70,
      3 1 3 60,
      3 2 1 20,
      3 2 2 30,
      3 2 3 30,
      3 2 4 20 };

// Convert first three columns into an integer,
// i.e. { 1 1 } -> 11, { 3 1 } -> 31
ncols = 2;
m = { 10, 1 };
grps = a[.,1:ncols]*m;

// Get unique groups
grps_unique = unique(grps);

// Convert groups into sequential class groups
idx = reclassify(grps, grps_unique, seqa(1, 1, rows(grps_unique)));

link

aptech

1,773